-5x-(-7x-4x)=2x(3x+4)

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Solution for -5x-(-7x-4x)=2x(3x+4) equation: 



-5x-(-7x-4x)=2x(3x+4)

We move all terms to the left:

-5x-(-7x-4x)-(2x(3x+4))=0

We add all the numbers together, and all the variables

-5x-(-11x)-(2x(3x+4))=0

We get rid of parentheses

-5x+11x-(2x(3x+4))=0



We calculate terms in parentheses: -(2x(3x+4)), so:

2x(3x+4)

We multiply parentheses

6x^2+8x

Back to the equation:

-(6x^2+8x)



We add all the numbers together, and all the variables

6x-(6x^2+8x)=0

We get rid of parentheses

-6x^2+6x-8x=0

We add all the numbers together, and all the variables

-6x^2-2x=0

a = -6; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-6)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-6}=\frac{0}{-12}
=0
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-6}=\frac{4}{-12}
=-1/3
$

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