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-5x-15=5x(x+3)
We move all terms to the left:
-5x-15-(5x(x+3))=0
We calculate terms in parentheses: -(5x(x+3)), so:We get rid of parentheses
5x(x+3)
We multiply parentheses
5x^2+15x
Back to the equation:
-(5x^2+15x)
-5x^2-5x-15x-15=0
We add all the numbers together, and all the variables
-5x^2-20x-15=0
a = -5; b = -20; c = -15;
Δ = b2-4ac
Δ = -202-4·(-5)·(-15)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-10}{2*-5}=\frac{10}{-10} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+10}{2*-5}=\frac{30}{-10} =-3 $
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