-5x-3/2(-8x-8)=-8(8x-8)-10

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Solution for -5x-3/2(-8x-8)=-8(8x-8)-10 equation: 



-5x-3/2(-8x-8)=-8(8x-8)-10

We move all terms to the left:

-5x-3/2(-8x-8)-(-8(8x-8)-10)=0



Domain of the equation: 2(-8x-8)!=0

x∈R



We multiply all the terms by the denominator


-5x*2(-8x-8)-((-8(8x-8)-10))*2(-8x-8)-3=0



We calculate terms in parentheses: -((-8(8x-8)-10))*2(-8x-8), so:

(-8(8x-8)-10))*2(-8x-8

We add all the numbers together, and all the variables

-8x+(-8(8x-8)-10))*2(-8

Back to the equation:

-(-8x+(-8(8x-8)-10))*2(-8)



Wy multiply elements

-10x^2(--(-8x+(-8(8x-8)-10))*2(-8)-3=0

We use the square of the difference formula

-10x^2(+(-8x+(-8(8x-8)-10))*2(-8)-3=0

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