-5x-3y=-41;x-2y=-10

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Solution for -5x-3y=-41;x-2y=-10 system of equations: 


  • /| 41-5*x-(3*y) = 0| x-(2*y)+10 = 0
  • We try to solve the equation: 41-5*x-(3*y) = 0
  • 41-5*x-3*y = 0 // - 41-5*x
  • -3*y = -(41-5*x) // : -3
  • y = (-(41-5*x))/(-3)
  • y = (41-5*x)/3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| x-(2*((41-5*x)/3))+10 = 0| y = (41-5*x)/3
  • (-1*2*(41-5*x))/3+x+10 = 0
  • 13/3*x-82/3+10 = 0
  • 13/3*x-52/3 = 0
  • 13/3*x-52/3 = 0 // + 52/3
  • 13/3*x = 52/3 // : 13/3
  • x = 52/3/13/3
  • x = 4
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (41-5*x)/3: 
  • y = (41-5*4)/3
  • y = (41-20)/3
  • y = 21/3
  • y = 7
  • We get a system of equations:
  • /| y = 7| x = 4

 

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