If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-5x^2+20=0
a = -5; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·(-5)·20
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*-5}=\frac{-20}{-10} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*-5}=\frac{20}{-10} =-2 $
| 11=3x+-1 | | X/2+x/8=30 | | -4x-7((-3x/4)+3/2)=-3 | | (3-5m)/4=8 | | x*x=84 | | x/7-2=5/7 | | x2-2x+24=0 | | 5/8s=15 | | 2(x-3)=4(2x-12) | | -2x2+48=4x | | x-3/5=1/3 | | x+62=9- | | -2z=-12/11 | | 8x-10/13x-2x=2/2 | | 14/10=42/x | | n=1/2=7/4 | | 0.5x–1.0675=3x–4.145 | | 3-x|2=-12 | | 7x=120-36 | | x²+6x+9=(3x-2)² | | 16x^2+7=16 | | 16x=34=18x+48 | | 3(x-1)^2(x+4)^7-5(x-1)^3(x+4)^6=0 | | 13.1=x•150 | | -3a+5=1 | | 6(3x-2)=2)4x-12 | | x-45+2x+6=180 | | (3(4w+3))/5=-11 | | 1/2x-1/6=49/12 | | x+18=x-41 | | X^2-12x=-17 | | 3−9x=30 |