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-5x^2+4x+33=0
a = -5; b = 4; c = +33;
Δ = b2-4ac
Δ = 42-4·(-5)·33
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-26}{2*-5}=\frac{-30}{-10} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+26}{2*-5}=\frac{22}{-10} =-2+1/5 $
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