-5x2+500=0

Solution for -5x2+500=0 equation:

-5x^2+500=0

a = -5; b = 0; c = +500;
Δ = b2-4ac
Δ = 02-4·(-5)·500
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100}{2*-5}=\frac{-100}{-10}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100}{2*-5}=\frac{100}{-10}
=-10
$