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-5x^2+65x+150=0
a = -5; b = 65; c = +150;
Δ = b2-4ac
Δ = 652-4·(-5)·150
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7225}=85$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-85}{2*-5}=\frac{-150}{-10} =+15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+85}{2*-5}=\frac{20}{-10} =-2 $
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