-5y(y-16)=y+(-71)

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Solution for -5y(y-16)=y+(-71) equation:



-5y(y-16)=y+(-71)
We move all terms to the left:
-5y(y-16)-(y+(-71))=0
We multiply parentheses
-5y^2+80y-(y+(-71))=0
We calculate terms in parentheses: -(y+(-71)), so:
y+(-71)
We add all the numbers together, and all the variables
y-71
Back to the equation:
-(y-71)
We get rid of parentheses
-5y^2+80y-y+71=0
We add all the numbers together, and all the variables
-5y^2+79y+71=0
a = -5; b = 79; c = +71;
Δ = b2-4ac
Δ = 792-4·(-5)·71
Δ = 7661
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(79)-\sqrt{7661}}{2*-5}=\frac{-79-\sqrt{7661}}{-10} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(79)+\sqrt{7661}}{2*-5}=\frac{-79+\sqrt{7661}}{-10} $

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