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-5y(y-6)=-15
We move all terms to the left:
-5y(y-6)-(-15)=0
We add all the numbers together, and all the variables
-5y(y-6)+15=0
We multiply parentheses
-5y^2+30y+15=0
a = -5; b = 30; c = +15;
Δ = b2-4ac
Δ = 302-4·(-5)·15
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-20\sqrt{3}}{2*-5}=\frac{-30-20\sqrt{3}}{-10} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+20\sqrt{3}}{2*-5}=\frac{-30+20\sqrt{3}}{-10} $
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