-5y+11=4(2y+4)y=

Solution for -5y+11=4(2y+4)y= equation:

-5y+11=4(2y+4)y=

We move all terms to the left:

-5y+11-(4(2y+4)y)=0


We calculate terms in parentheses: -(4(2y+4)y), so:

4(2y+4)y

We multiply parentheses

8y^2+16y

Back to the equation:

-(8y^2+16y)


We get rid of parentheses

-8y^2-5y-16y+11=0

We add all the numbers together, and all the variables

-8y^2-21y+11=0

a = -8; b = -21; c = +11;
Δ = b2-4ac
Δ = -212-4·(-8)·11
Δ = 793
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{793}}{2*-8}=\frac{21-\sqrt{793}}{-16}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{793}}{2*-8}=\frac{21+\sqrt{793}}{-16}
$