-5y+30=5(3y-2)-12y

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Solution for -5y+30=5(3y-2)-12y equation: 



-5y+30=5(3y-2)-12y

We move all terms to the left:

-5y+30-(5(3y-2)-12y)=0



We calculate terms in parentheses: -(5(3y-2)-12y), so:

5(3y-2)-12y

We add all the numbers together, and all the variables

-12y+5(3y-2)

We multiply parentheses

-12y+15y-10

We add all the numbers together, and all the variables

3y-10

Back to the equation:

-(3y-10)



We get rid of parentheses

-5y-3y+10+30=0

We add all the numbers together, and all the variables

-8y+40=0

We move all terms containing y to the left, all other terms to the right

-8y=-40

y=-40/-8

y=+5

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