-5y+8(3y-2)=-8-5(-8-y)

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Solution for -5y+8(3y-2)=-8-5(-8-y) equation: 



-5y+8(3y-2)=-8-5(-8-y)

We move all terms to the left:

-5y+8(3y-2)-(-8-5(-8-y))=0

We add all the numbers together, and all the variables

-5y+8(3y-2)-(-8-5(-1y-8))=0

We multiply parentheses

-5y+24y-(-8-5(-1y-8))-16=0



We calculate terms in parentheses: -(-8-5(-1y-8)), so:

-8-5(-1y-8)

determiningTheFunctionDomain
-5(-1y-8)-8

We multiply parentheses

5y+40-8

We add all the numbers together, and all the variables

5y+32

Back to the equation:

-(5y+32)



We add all the numbers together, and all the variables

19y-(5y+32)-16=0

We get rid of parentheses

19y-5y-32-16=0

We add all the numbers together, and all the variables

14y-48=0

We move all terms containing y to the left, all other terms to the right

14y=48

y=48/14

y=3+3/7

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