-5y-10=2-(4+y)

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Solution for -5y-10=2-(4+y) equation: 



-5y-10=2-(4+y)

We move all terms to the left:

-5y-10-(2-(4+y))=0

We add all the numbers together, and all the variables

-5y-(2-(y+4))-10=0



We calculate terms in parentheses: -(2-(y+4)), so:

2-(y+4)

determiningTheFunctionDomain
-(y+4)+2

We get rid of parentheses

-y-4+2

We add all the numbers together, and all the variables

-1y-2

Back to the equation:

-(-1y-2)



We get rid of parentheses

-5y+1y+2-10=0

We add all the numbers together, and all the variables

-4y-8=0

We move all terms containing y to the left, all other terms to the right

-4y=8

y=8/-4

y=-2

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