-6(-2b-3)=102

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Solution for -6(-2b-3)=102 equation: 



-6(-2b-3)=102

We move all terms to the left:

-6(-2b-3)-(102)=0

We multiply parentheses

12b+18-102=0

We add all the numbers together, and all the variables

12b-84=0

We move all terms containing b to the left, all other terms to the right

12b=84

b=84/12

b=7

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