-6(-2v+1)-v=2(v-1)-1

Solution for -6(-2v+1)-v=2(v-1)-1 equation:

-6(-2v+1)-v=2(v-1)-1

We move all terms to the left:

-6(-2v+1)-v-(2(v-1)-1)=0

We add all the numbers together, and all the variables

-1v-6(-2v+1)-(2(v-1)-1)=0

We multiply parentheses

-1v+12v-(2(v-1)-1)-6=0


We calculate terms in parentheses: -(2(v-1)-1), so:

2(v-1)-1

We multiply parentheses

2v-2-1

We add all the numbers together, and all the variables

2v-3

Back to the equation:

-(2v-3)


We add all the numbers together, and all the variables

11v-(2v-3)-6=0

We get rid of parentheses

11v-2v+3-6=0

We add all the numbers together, and all the variables

9v-3=0

We move all terms containing v to the left, all other terms to the right

9v=3

v=3/9

v=1/3