-6(-2y+1)-4y=2(y-1)-1

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Solution for -6(-2y+1)-4y=2(y-1)-1 equation: 



-6(-2y+1)-4y=2(y-1)-1

We move all terms to the left:

-6(-2y+1)-4y-(2(y-1)-1)=0

We add all the numbers together, and all the variables

-4y-6(-2y+1)-(2(y-1)-1)=0

We multiply parentheses

-4y+12y-(2(y-1)-1)-6=0



We calculate terms in parentheses: -(2(y-1)-1), so:

2(y-1)-1

We multiply parentheses

2y-2-1

We add all the numbers together, and all the variables

2y-3

Back to the equation:

-(2y-3)



We add all the numbers together, and all the variables

8y-(2y-3)-6=0

We get rid of parentheses

8y-2y+3-6=0

We add all the numbers together, and all the variables

6y-3=0

We move all terms containing y to the left, all other terms to the right

6y=3

y=3/6

y=1/2

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