-6(-3u+1)-7u=3(u-3)-3

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Solution for -6(-3u+1)-7u=3(u-3)-3 equation: 



-6(-3u+1)-7u=3(u-3)-3

We move all terms to the left:

-6(-3u+1)-7u-(3(u-3)-3)=0

We add all the numbers together, and all the variables

-7u-6(-3u+1)-(3(u-3)-3)=0

We multiply parentheses

-7u+18u-(3(u-3)-3)-6=0



We calculate terms in parentheses: -(3(u-3)-3), so:

3(u-3)-3

We multiply parentheses

3u-9-3

We add all the numbers together, and all the variables

3u-12

Back to the equation:

-(3u-12)



We add all the numbers together, and all the variables

11u-(3u-12)-6=0

We get rid of parentheses

11u-3u+12-6=0

We add all the numbers together, and all the variables

8u+6=0

We move all terms containing u to the left, all other terms to the right

8u=-6

u=-6/8

u=-3/4

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