-6(-3u+3)-4u=4(u-1)-2

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Solution for -6(-3u+3)-4u=4(u-1)-2 equation: 



-6(-3u+3)-4u=4(u-1)-2

We move all terms to the left:

-6(-3u+3)-4u-(4(u-1)-2)=0

We add all the numbers together, and all the variables

-4u-6(-3u+3)-(4(u-1)-2)=0

We multiply parentheses

-4u+18u-(4(u-1)-2)-18=0



We calculate terms in parentheses: -(4(u-1)-2), so:

4(u-1)-2

We multiply parentheses

4u-4-2

We add all the numbers together, and all the variables

4u-6

Back to the equation:

-(4u-6)



We add all the numbers together, and all the variables

14u-(4u-6)-18=0

We get rid of parentheses

14u-4u+6-18=0

We add all the numbers together, and all the variables

10u-12=0

We move all terms containing u to the left, all other terms to the right

10u=12

u=12/10

u=1+1/5

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