-6(-3v+2)=2(v-3)-4

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Solution for -6(-3v+2)=2(v-3)-4 equation: 



-6(-3v+2)=2(v-3)-4

We move all terms to the left:

-6(-3v+2)-(2(v-3)-4)=0

We multiply parentheses

18v-(2(v-3)-4)-12=0



We calculate terms in parentheses: -(2(v-3)-4), so:

2(v-3)-4

We multiply parentheses

2v-6-4

We add all the numbers together, and all the variables

2v-10

Back to the equation:

-(2v-10)



We get rid of parentheses

18v-2v+10-12=0

We add all the numbers together, and all the variables

16v-2=0

We move all terms containing v to the left, all other terms to the right

16v=2

v=2/16

v=1/8

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