-6(-4u+1)-6u=2(u-3)-2

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Solution for -6(-4u+1)-6u=2(u-3)-2 equation: 



-6(-4u+1)-6u=2(u-3)-2

We move all terms to the left:

-6(-4u+1)-6u-(2(u-3)-2)=0

We add all the numbers together, and all the variables

-6u-6(-4u+1)-(2(u-3)-2)=0

We multiply parentheses

-6u+24u-(2(u-3)-2)-6=0



We calculate terms in parentheses: -(2(u-3)-2), so:

2(u-3)-2

We multiply parentheses

2u-6-2

We add all the numbers together, and all the variables

2u-8

Back to the equation:

-(2u-8)



We add all the numbers together, and all the variables

18u-(2u-8)-6=0

We get rid of parentheses

18u-2u+8-6=0

We add all the numbers together, and all the variables

16u+2=0

We move all terms containing u to the left, all other terms to the right

16u=-2

u=-2/16

u=-1/8

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