-6(-4y+3)-4y=2(y-4)-2

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Solution for -6(-4y+3)-4y=2(y-4)-2 equation: 



-6(-4y+3)-4y=2(y-4)-2

We move all terms to the left:

-6(-4y+3)-4y-(2(y-4)-2)=0

We add all the numbers together, and all the variables

-4y-6(-4y+3)-(2(y-4)-2)=0

We multiply parentheses

-4y+24y-(2(y-4)-2)-18=0



We calculate terms in parentheses: -(2(y-4)-2), so:

2(y-4)-2

We multiply parentheses

2y-8-2

We add all the numbers together, and all the variables

2y-10

Back to the equation:

-(2y-10)



We add all the numbers together, and all the variables

20y-(2y-10)-18=0

We get rid of parentheses

20y-2y+10-18=0

We add all the numbers together, and all the variables

18y-8=0

We move all terms containing y to the left, all other terms to the right

18y=8

y=8/18

y=4/9

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