-6(-4y+3)-8y=6(y-4)-2

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Solution for -6(-4y+3)-8y=6(y-4)-2 equation: 



-6(-4y+3)-8y=6(y-4)-2

We move all terms to the left:

-6(-4y+3)-8y-(6(y-4)-2)=0

We add all the numbers together, and all the variables

-8y-6(-4y+3)-(6(y-4)-2)=0

We multiply parentheses

-8y+24y-(6(y-4)-2)-18=0



We calculate terms in parentheses: -(6(y-4)-2), so:

6(y-4)-2

We multiply parentheses

6y-24-2

We add all the numbers together, and all the variables

6y-26

Back to the equation:

-(6y-26)



We add all the numbers together, and all the variables

16y-(6y-26)-18=0

We get rid of parentheses

16y-6y+26-18=0

We add all the numbers together, and all the variables

10y+8=0

We move all terms containing y to the left, all other terms to the right

10y=-8

y=-8/10

y=-4/5

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