-6(1+b)=3(2b-2)

Solution for -6(1+b)=3(2b-2) equation:

Simplifying
-6(1 + b) = 3(2b + -2)
(1 * -6 + b * -6) = 3(2b + -2)
(-6 + -6b) = 3(2b + -2)

Reorder the terms:
-6 + -6b = 3(-2 + 2b)
-6 + -6b = (-2 * 3 + 2b * 3)
-6 + -6b = (-6 + 6b)

Add '6' to each side of the equation.
-6 + 6 + -6b = -6 + 6 + 6b

Combine like terms: -6 + 6 = 0
0 + -6b = -6 + 6 + 6b
-6b = -6 + 6 + 6b

Combine like terms: -6 + 6 = 0
-6b = 0 + 6b
-6b = 6b

Solving
-6b = 6b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-6b' to each side of the equation.
-6b + -6b = 6b + -6b

Combine like terms: -6b + -6b = -12b
-12b = 6b + -6b

Combine like terms: 6b + -6b = 0
-12b = 0

Divide each side by '-12'.
b = 0

Simplifying
b = 0