-6(1+n)=48+3n

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Solution for -6(1+n)=48+3n equation: 



-6(1+n)=48+3n

We move all terms to the left:

-6(1+n)-(48+3n)=0

We add all the numbers together, and all the variables

-6(n+1)-(3n+48)=0

We multiply parentheses

-6n-(3n+48)-6=0

We get rid of parentheses

-6n-3n-48-6=0

We add all the numbers together, and all the variables

-9n-54=0

We move all terms containing n to the left, all other terms to the right

-9n=54

n=54/-9

n=-6

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