-6(1-2b)=9(b+4)-3

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Solution for -6(1-2b)=9(b+4)-3 equation: 



-6(1-2b)=9(b+4)-3

We move all terms to the left:

-6(1-2b)-(9(b+4)-3)=0

We add all the numbers together, and all the variables

-6(-2b+1)-(9(b+4)-3)=0

We multiply parentheses

12b-(9(b+4)-3)-6=0



We calculate terms in parentheses: -(9(b+4)-3), so:

9(b+4)-3

We multiply parentheses

9b+36-3

We add all the numbers together, and all the variables

9b+33

Back to the equation:

-(9b+33)



We get rid of parentheses

12b-9b-33-6=0

We add all the numbers together, and all the variables

3b-39=0

We move all terms containing b to the left, all other terms to the right

3b=39

b=39/3

b=13

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