-6(2c+4)-1=2(c+5)

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Solution for -6(2c+4)-1=2(c+5) equation: 



-6(2c+4)-1=2(c+5)

We move all terms to the left:

-6(2c+4)-1-(2(c+5))=0

We multiply parentheses

-12c-(2(c+5))-24-1=0



We calculate terms in parentheses: -(2(c+5)), so:

2(c+5)

We multiply parentheses

2c+10

Back to the equation:

-(2c+10)



We add all the numbers together, and all the variables

-12c-(2c+10)-25=0

We get rid of parentheses

-12c-2c-10-25=0

We add all the numbers together, and all the variables

-14c-35=0

We move all terms containing c to the left, all other terms to the right

-14c=35

c=35/-14

c=-2+1/2

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