-6(2f+5)=20

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Solution for -6(2f+5)=20 equation: 



-6(2f+5)=20

We move all terms to the left:

-6(2f+5)-(20)=0

We multiply parentheses

-12f-30-20=0

We add all the numbers together, and all the variables

-12f-50=0

We move all terms containing f to the left, all other terms to the right

-12f=50

f=50/-12

f=-4+1/6

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