-6(2m+2)+4(3+4m)=28

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Solution for -6(2m+2)+4(3+4m)=28 equation: 



-6(2m+2)+4(3+4m)=28

We move all terms to the left:

-6(2m+2)+4(3+4m)-(28)=0

We add all the numbers together, and all the variables

-6(2m+2)+4(4m+3)-28=0

We multiply parentheses

-12m+16m-12+12-28=0

We add all the numbers together, and all the variables

4m-28=0

We move all terms containing m to the left, all other terms to the right

4m=28

m=28/4

m=7

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