-6(2m+3)=2(8m+19)

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Solution for -6(2m+3)=2(8m+19) equation: 



-6(2m+3)=2(8m+19)

We move all terms to the left:

-6(2m+3)-(2(8m+19))=0

We multiply parentheses

-12m-(2(8m+19))-18=0



We calculate terms in parentheses: -(2(8m+19)), so:

2(8m+19)

We multiply parentheses

16m+38

Back to the equation:

-(16m+38)



We get rid of parentheses

-12m-16m-38-18=0

We add all the numbers together, and all the variables

-28m-56=0

We move all terms containing m to the left, all other terms to the right

-28m=56

m=56/-28

m=-2

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