-6(2r+8)=10(r/3)

Solution for -6(2r+8)=10(r/3) equation:

-6(2r+8)=10(r/3)

We move all terms to the left:

-6(2r+8)-(10(r/3))=0

We add all the numbers together, and all the variables

-6(2r+8)-(10(+r/3))=0

We multiply parentheses

-12r-(10(+r/3))-48=0

We multiply all the terms by the denominator


-12r*3))-(10(+r-48*3))=0

We add all the numbers together, and all the variables

-12r*3))-(10(r-144))=0

We add all the numbers together, and all the variables

-12r*3))-(10(r=0

Wy multiply elements

-36r^2=0

a = -36; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-36)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{-72}=0$