-6(2r+8)=10(r/3)

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Solution for -6(2r+8)=10(r/3) equation:



-6(2r+8)=10(r/3)
We move all terms to the left:
-6(2r+8)-(10(r/3))=0
We add all the numbers together, and all the variables
-6(2r+8)-(10(+r/3))=0
We multiply parentheses
-12r-(10(+r/3))-48=0
We multiply all the terms by the denominator
-12r*3))-(10(+r-48*3))=0
We add all the numbers together, and all the variables
-12r*3))-(10(r-144))=0
We add all the numbers together, and all the variables
-12r*3))-(10(r=0
Wy multiply elements
-36r^2=0
a = -36; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-36)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{-72}=0$

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