-6(2r-2)=-r+40

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Solution for -6(2r-2)=-r+40 equation: 



-6(2r-2)=-r+40

We move all terms to the left:

-6(2r-2)-(-r+40)=0

We add all the numbers together, and all the variables

-6(2r-2)-(-1r+40)=0

We multiply parentheses

-12r-(-1r+40)+12=0

We get rid of parentheses

-12r+1r-40+12=0

We add all the numbers together, and all the variables

-11r-28=0

We move all terms containing r to the left, all other terms to the right

-11r=28

r=28/-11

r=-2+6/11

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