-6(2r-3)-8=5(-8r+2)

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Solution for -6(2r-3)-8=5(-8r+2) equation: 



-6(2r-3)-8=5(-8r+2)

We move all terms to the left:

-6(2r-3)-8-(5(-8r+2))=0

We multiply parentheses

-12r-(5(-8r+2))+18-8=0



We calculate terms in parentheses: -(5(-8r+2)), so:

5(-8r+2)

We multiply parentheses

-40r+10

Back to the equation:

-(-40r+10)



We add all the numbers together, and all the variables

-12r-(-40r+10)+10=0

We get rid of parentheses

-12r+40r-10+10=0

We add all the numbers together, and all the variables

28r=0

r=0/28

r=0

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