-6(2u-8)+7u=7(u+8)

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Solution for -6(2u-8)+7u=7(u+8) equation: 



-6(2u-8)+7u=7(u+8)

We move all terms to the left:

-6(2u-8)+7u-(7(u+8))=0

We add all the numbers together, and all the variables

7u-6(2u-8)-(7(u+8))=0

We multiply parentheses

7u-12u-(7(u+8))+48=0



We calculate terms in parentheses: -(7(u+8)), so:

7(u+8)

We multiply parentheses

7u+56

Back to the equation:

-(7u+56)



We add all the numbers together, and all the variables

-5u-(7u+56)+48=0

We get rid of parentheses

-5u-7u-56+48=0

We add all the numbers together, and all the variables

-12u-8=0

We move all terms containing u to the left, all other terms to the right

-12u=8

u=8/-12

u=-2/3

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