-6(2y+8)=10(y-3)

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Solution for -6(2y+8)=10(y-3) equation: 



-6(2y+8)=10(y-3)

We move all terms to the left:

-6(2y+8)-(10(y-3))=0

We multiply parentheses

-12y-(10(y-3))-48=0



We calculate terms in parentheses: -(10(y-3)), so:

10(y-3)

We multiply parentheses

10y-30

Back to the equation:

-(10y-30)



We get rid of parentheses

-12y-10y+30-48=0

We add all the numbers together, and all the variables

-22y-18=0

We move all terms containing y to the left, all other terms to the right

-22y=18

y=18/-22

y=-9/11

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