-6(2y+8)=10(y-3)

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Solution for -6(2y+8)=10(y-3) equation:



-6(2y+8)=10(y-3)
We move all terms to the left:
-6(2y+8)-(10(y-3))=0
We multiply parentheses
-12y-(10(y-3))-48=0
We calculate terms in parentheses: -(10(y-3)), so:
10(y-3)
We multiply parentheses
10y-30
Back to the equation:
-(10y-30)
We get rid of parentheses
-12y-10y+30-48=0
We add all the numbers together, and all the variables
-22y-18=0
We move all terms containing y to the left, all other terms to the right
-22y=18
y=18/-22
y=-9/11

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