-6(2y-1)+8y=2(y+8

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Solution for -6(2y-1)+8y=2(y+8 equation:



-6(2y-1)+8y=2(y+8
We move all terms to the left:
-6(2y-1)+8y-(2(y+8)=0
We add all the numbers together, and all the variables
8y-6(2y-1)-(2(y+8)=0
We multiply parentheses
8y-12y-(2(y+8)+6=0
We add all the numbers together, and all the variables
-4y-(2(y+8)+6=0

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