-6(2y-2)+7y=5(y+4)

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Solution for -6(2y-2)+7y=5(y+4) equation:



-6(2y-2)+7y=5(y+4)
We move all terms to the left:
-6(2y-2)+7y-(5(y+4))=0
We add all the numbers together, and all the variables
7y-6(2y-2)-(5(y+4))=0
We multiply parentheses
7y-12y-(5(y+4))+12=0
We calculate terms in parentheses: -(5(y+4)), so:
5(y+4)
We multiply parentheses
5y+20
Back to the equation:
-(5y+20)
We add all the numbers together, and all the variables
-5y-(5y+20)+12=0
We get rid of parentheses
-5y-5y-20+12=0
We add all the numbers together, and all the variables
-10y-8=0
We move all terms containing y to the left, all other terms to the right
-10y=8
y=8/-10
y=-4/5

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