-6(2y-3)+6y=6(y+6)

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Solution for -6(2y-3)+6y=6(y+6) equation: 



-6(2y-3)+6y=6(y+6)

We move all terms to the left:

-6(2y-3)+6y-(6(y+6))=0

We add all the numbers together, and all the variables

6y-6(2y-3)-(6(y+6))=0

We multiply parentheses

6y-12y-(6(y+6))+18=0



We calculate terms in parentheses: -(6(y+6)), so:

6(y+6)

We multiply parentheses

6y+36

Back to the equation:

-(6y+36)



We add all the numbers together, and all the variables

-6y-(6y+36)+18=0

We get rid of parentheses

-6y-6y-36+18=0

We add all the numbers together, and all the variables

-12y-18=0

We move all terms containing y to the left, all other terms to the right

-12y=18

y=18/-12

y=-1+1/2

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