-6(3+x)=3(x-3)-4x

Solution for -6(3+x)=3(x-3)-4x equation:

-6(3+x)=3(x-3)-4x

We move all terms to the left:

-6(3+x)-(3(x-3)-4x)=0

We add all the numbers together, and all the variables

-6(x+3)-(3(x-3)-4x)=0

We multiply parentheses

-6x-(3(x-3)-4x)-18=0


We calculate terms in parentheses: -(3(x-3)-4x), so:

3(x-3)-4x

We add all the numbers together, and all the variables

-4x+3(x-3)

We multiply parentheses

-4x+3x-9

We add all the numbers together, and all the variables

-1x-9

Back to the equation:

-(-1x-9)


We get rid of parentheses

-6x+1x+9-18=0

We add all the numbers together, and all the variables

-5x-9=0

We move all terms containing x to the left, all other terms to the right

-5x=9

x=9/-5

x=-1+4/5