-6(3-x)+1=2(x-3)

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Solution for -6(3-x)+1=2(x-3) equation: 



-6(3-x)+1=2(x-3)

We move all terms to the left:

-6(3-x)+1-(2(x-3))=0

We add all the numbers together, and all the variables

-6(-1x+3)-(2(x-3))+1=0

We multiply parentheses

6x-(2(x-3))-18+1=0



We calculate terms in parentheses: -(2(x-3)), so:

2(x-3)

We multiply parentheses

2x-6

Back to the equation:

-(2x-6)



We add all the numbers together, and all the variables

6x-(2x-6)-17=0

We get rid of parentheses

6x-2x+6-17=0

We add all the numbers together, and all the variables

4x-11=0

We move all terms containing x to the left, all other terms to the right

4x=11

x=11/4

x=2+3/4

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