-6(3-x)=-6(3-x)+7(2x+1)

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Solution for -6(3-x)=-6(3-x)+7(2x+1) equation: 



-6(3-x)=-6(3-x)+7(2x+1)

We move all terms to the left:

-6(3-x)-(-6(3-x)+7(2x+1))=0

We add all the numbers together, and all the variables

-6(-1x+3)-(-6(-1x+3)+7(2x+1))=0

We multiply parentheses

6x-(-6(-1x+3)+7(2x+1))-18=0



We calculate terms in parentheses: -(-6(-1x+3)+7(2x+1)), so:

-6(-1x+3)+7(2x+1)

We multiply parentheses

6x+14x-18+7

We add all the numbers together, and all the variables

20x-11

Back to the equation:

-(20x-11)



We get rid of parentheses

6x-20x+11-18=0

We add all the numbers together, and all the variables

-14x-7=0

We move all terms containing x to the left, all other terms to the right

-14x=7

x=7/-14

x=-1/2

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