-6(3b+1)+(19b-2)=0

Solution for -6(3b+1)+(19b-2)=0 equation:

Simplifying
-6(3b + 1) + (19b + -2) = 0

Reorder the terms:
-6(1 + 3b) + (19b + -2) = 0
(1 * -6 + 3b * -6) + (19b + -2) = 0
(-6 + -18b) + (19b + -2) = 0

Reorder the terms:
-6 + -18b + (-2 + 19b) = 0

Remove parenthesis around (-2 + 19b)
-6 + -18b + -2 + 19b = 0

Reorder the terms:
-6 + -2 + -18b + 19b = 0

Combine like terms: -6 + -2 = -8
-8 + -18b + 19b = 0

Combine like terms: -18b + 19b = 1b
-8 + 1b = 0

Solving
-8 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 1b = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 1b = 0 + 8
1b = 0 + 8

Combine like terms: 0 + 8 = 8
1b = 8

Divide each side by '1'.
b = 8

Simplifying
b = 8