-6(3b+1)+(19b-3)=0

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Solution for -6(3b+1)+(19b-3)=0 equation:


Simplifying
-6(3b + 1) + (19b + -3) = 0

Reorder the terms:
-6(1 + 3b) + (19b + -3) = 0
(1 * -6 + 3b * -6) + (19b + -3) = 0
(-6 + -18b) + (19b + -3) = 0

Reorder the terms:
-6 + -18b + (-3 + 19b) = 0

Remove parenthesis around (-3 + 19b)
-6 + -18b + -3 + 19b = 0

Reorder the terms:
-6 + -3 + -18b + 19b = 0

Combine like terms: -6 + -3 = -9
-9 + -18b + 19b = 0

Combine like terms: -18b + 19b = 1b
-9 + 1b = 0

Solving
-9 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 1b = 0 + 9

Combine like terms: -9 + 9 = 0
0 + 1b = 0 + 9
1b = 0 + 9

Combine like terms: 0 + 9 = 9
1b = 9

Divide each side by '1'.
b = 9

Simplifying
b = 9

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