-6(3b+1)+(19b-4)=0

Solution for -6(3b+1)+(19b-4)=0 equation:

Simplifying
-6(3b + 1) + (19b + -4) = 0

Reorder the terms:
-6(1 + 3b) + (19b + -4) = 0
(1 * -6 + 3b * -6) + (19b + -4) = 0
(-6 + -18b) + (19b + -4) = 0

Reorder the terms:
-6 + -18b + (-4 + 19b) = 0

Remove parenthesis around (-4 + 19b)
-6 + -18b + -4 + 19b = 0

Reorder the terms:
-6 + -4 + -18b + 19b = 0

Combine like terms: -6 + -4 = -10
-10 + -18b + 19b = 0

Combine like terms: -18b + 19b = 1b
-10 + 1b = 0

Solving
-10 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 1b = 0 + 10

Combine like terms: -10 + 10 = 0
0 + 1b = 0 + 10
1b = 0 + 10

Combine like terms: 0 + 10 = 10
1b = 10

Divide each side by '1'.
b = 10

Simplifying
b = 10