-6(3b+2)+(19b-4)=0

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Solution for -6(3b+2)+(19b-4)=0 equation:


Simplifying
-6(3b + 2) + (19b + -4) = 0

Reorder the terms:
-6(2 + 3b) + (19b + -4) = 0
(2 * -6 + 3b * -6) + (19b + -4) = 0
(-12 + -18b) + (19b + -4) = 0

Reorder the terms:
-12 + -18b + (-4 + 19b) = 0

Remove parenthesis around (-4 + 19b)
-12 + -18b + -4 + 19b = 0

Reorder the terms:
-12 + -4 + -18b + 19b = 0

Combine like terms: -12 + -4 = -16
-16 + -18b + 19b = 0

Combine like terms: -18b + 19b = 1b
-16 + 1b = 0

Solving
-16 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 1b = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 1b = 0 + 16
1b = 0 + 16

Combine like terms: 0 + 16 = 16
1b = 16

Divide each side by '1'.
b = 16

Simplifying
b = 16

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