-6(3b-2)-3=99

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Solution for -6(3b-2)-3=99 equation:



-6(3b-2)-3=99
We move all terms to the left:
-6(3b-2)-3-(99)=0
We add all the numbers together, and all the variables
-6(3b-2)-102=0
We multiply parentheses
-18b+12-102=0
We add all the numbers together, and all the variables
-18b-90=0
We move all terms containing b to the left, all other terms to the right
-18b=90
b=90/-18
b=-5

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