-6(3v+4)-7v=2(v-1)-7

Solution for -6(3v+4)-7v=2(v-1)-7 equation:

-6(3v+4)-7v=2(v-1)-7

We move all terms to the left:

-6(3v+4)-7v-(2(v-1)-7)=0

We add all the numbers together, and all the variables

-7v-6(3v+4)-(2(v-1)-7)=0

We multiply parentheses

-7v-18v-(2(v-1)-7)-24=0


We calculate terms in parentheses: -(2(v-1)-7), so:

2(v-1)-7

We multiply parentheses

2v-2-7

We add all the numbers together, and all the variables

2v-9

Back to the equation:

-(2v-9)


We add all the numbers together, and all the variables

-25v-(2v-9)-24=0

We get rid of parentheses

-25v-2v+9-24=0

We add all the numbers together, and all the variables

-27v-15=0

We move all terms containing v to the left, all other terms to the right

-27v=15

v=15/-27

v=-5/9