-6(3x+1)+(19x-2)=0

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Solution for -6(3x+1)+(19x-2)=0 equation:


Simplifying
-6(3x + 1) + (19x + -2) = 0

Reorder the terms:
-6(1 + 3x) + (19x + -2) = 0
(1 * -6 + 3x * -6) + (19x + -2) = 0
(-6 + -18x) + (19x + -2) = 0

Reorder the terms:
-6 + -18x + (-2 + 19x) = 0

Remove parenthesis around (-2 + 19x)
-6 + -18x + -2 + 19x = 0

Reorder the terms:
-6 + -2 + -18x + 19x = 0

Combine like terms: -6 + -2 = -8
-8 + -18x + 19x = 0

Combine like terms: -18x + 19x = 1x
-8 + 1x = 0

Solving
-8 + 1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 1x = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 1x = 0 + 8
1x = 0 + 8

Combine like terms: 0 + 8 = 8
1x = 8

Divide each side by '1'.
x = 8

Simplifying
x = 8

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