-6(3x+3)=3(11-4x)-39

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Solution for -6(3x+3)=3(11-4x)-39 equation:



-6(3x+3)=3(11-4x)-39
We move all terms to the left:
-6(3x+3)-(3(11-4x)-39)=0
We add all the numbers together, and all the variables
-6(3x+3)-(3(-4x+11)-39)=0
We multiply parentheses
-18x-(3(-4x+11)-39)-18=0
We calculate terms in parentheses: -(3(-4x+11)-39), so:
3(-4x+11)-39
We multiply parentheses
-12x+33-39
We add all the numbers together, and all the variables
-12x-6
Back to the equation:
-(-12x-6)
We get rid of parentheses
-18x+12x+6-18=0
We add all the numbers together, and all the variables
-6x-12=0
We move all terms containing x to the left, all other terms to the right
-6x=12
x=12/-6
x=-2

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