-6(3x+3)=3(11-4x)-39

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Solution for -6(3x+3)=3(11-4x)-39 equation: 



-6(3x+3)=3(11-4x)-39

We move all terms to the left:

-6(3x+3)-(3(11-4x)-39)=0

We add all the numbers together, and all the variables

-6(3x+3)-(3(-4x+11)-39)=0

We multiply parentheses

-18x-(3(-4x+11)-39)-18=0



We calculate terms in parentheses: -(3(-4x+11)-39), so:

3(-4x+11)-39

We multiply parentheses

-12x+33-39

We add all the numbers together, and all the variables

-12x-6

Back to the equation:

-(-12x-6)



We get rid of parentheses

-18x+12x+6-18=0

We add all the numbers together, and all the variables

-6x-12=0

We move all terms containing x to the left, all other terms to the right

-6x=12

x=12/-6

x=-2

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