-6(3x-2)+4=18x+16

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Solution for -6(3x-2)+4=18x+16 equation: 



-6(3x-2)+4=18x+16

We move all terms to the left:

-6(3x-2)+4-(18x+16)=0

We multiply parentheses

-18x-(18x+16)+12+4=0

We get rid of parentheses

-18x-18x-16+12+4=0

We add all the numbers together, and all the variables

-36x=0

x=0/-36

x=0

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